Question

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Answer 1

`\large \boxed{\sf \bold{A.} \ x=11.21}`

Explanation:

`\large \sf log_3 (x)=2.2`

Solve this by converting the logarithmic statement into its equivalent exponential form, using the relationship:

`\large \sf log_b(y)=x`

`\large{\sf y=b^x}`

Apply the relationship.

`\large \sf log_3 (x)=2.2`

`\large \sf x=3^(2.2)`

`\large \sf x=11.21157845...`

`\large \sf x \approx 11.21`

Answer 2

11.21157846 =x

Explanation:

We know log b (a) = c can be written as b^c =a

log 3 (x) = 2.2

3^2.2 = x

11.21157846 =x