Answer:
The correct answers for both of them is -2 and 0.
Explanation:
I)
![(f\circ g)(2)=f(g(2))](https://img.qammunity.org/2021/formulas/mathematics/middle-school/zqoaloo9xzqjwpj91aquruiq8g6qana7oq.png)
From the red graph, we can see that g(2) is 0.
Therefore, f(g(2)) is equal to f(0).
And from the blue graph, we can see that f(0) is -2.
Therefore:
![(f\circ g)(2)=-2](https://img.qammunity.org/2021/formulas/mathematics/middle-school/v6znwj493csdxcc59srzlz04j3vehw3pw2.png)
II)
![(g\circ f)(1)=g(f(1))](https://img.qammunity.org/2021/formulas/mathematics/middle-school/31ess6psv4n97ghv1jfuwh0gkax12dypef.png)
From the blue graph, we can see that f(1) is 0.
Therefore, g(f(1)) is equal to g(0).
And from the red graph, g(0) is 0.
Therefore:
![(g\circ f)(1)=0](https://img.qammunity.org/2021/formulas/mathematics/middle-school/69the2ujuyr25ko3r6706jjp7zs1jugt4t.png)
So, you got one correct. Nicely done!