Question

A sharp edged orifice with a 60 mm diameter opening in the vertical side of a large tank discharges under a head of 6 m. If the coefficient of contraction is 0.68 and the coefficient of velocity is 0.92, what is the discharge?

Answer 1

The discharge rate is
`Q = 0.0192 \ m^3 /s`

Step-by-step explanation:

From the question we are told that

The diameter is
`d = 60 \ mm = 0.06 \ m`

The head is
`h = 6 \ m`

The coefficient of contraction is
`Cc = 0.68`

The coefficient of velocity is
`Cv = 0.92`

The radius is mathematically evaluated as

`r = (d)/(2)`

substituting values

`r = ( 0.06 )/(2)`

`r = 0.03 \ m`

The area is mathematically represented as

`A = \pi r^2`

substituting values

`A = 3.142 * (0.03)^2`

`A = 0.00283 \ m^2`

The discharge rate is mathematically represented as

`Q = Cv *Cc * A * √( 2 * g * h)`

substituting values

`Q = 0.68 * 0.92* 0.00283 * √( 2 * 9.8 * 6)`

`Q = 0.0192 \ m^3 /s`