Answer:
sin(θ) = (2/5)√6
Explanation:
The sine and cosine are related by the formula ...
![sin((\theta))^2+cos((\theta))^2=1\\\\sin((\theta))=\pm√(1-cos((\theta))^2)](https://img.qammunity.org/2021/formulas/mathematics/high-school/lqzdch6r4qnslh39qtanq40s04wyn07v89.png)
Filling in the given value for cos(θ), we find the sine to be ...
![sin((\theta))=\pm\sqrt{1-\left((1)/(5)\right)^2}=\pm(√(24))/(5)=\pm(2)/(5)√(6)](https://img.qammunity.org/2021/formulas/mathematics/high-school/g8o1hkwo1f1ldo77ugt4snz1b5eoijrofk.png)
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The cosine function is positive for angles in both the first and fourth quadrants. The restriction on θ tells us this is a first-quadrant angle. The sine is positive in the first quadrant, so the desired value is ...
sin(θ) = (2/5)√6