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HELPP! QUICKKKK! Lol

Problem:
Last year I attended the Jurassic World Dinosaur Exhibit with my family and my friend and her family. My
family includes 2 adults (including myself) and my child we paid a total of $94. Her family includes 2
adults and 2 children she paid a total of $110. What was the admission price for an adult ticket and how
much was it for the admission price for a child ticket?
Let a represent adult ticket price
Let c represent child ticket price

User Styxxy
by
5.8k points

2 Answers

2 votes
Child= $16 and Adult= $39
Because, for the first family 39a+16c= $94 total for that family and just do the math for the other one :)
User BrownEye
by
4.9k points
1 vote

Answer:

Child ticket = $16.

Explanation:

Let adult tickets = a;

child ticket = c.

2a + c = 94 — eq no. 1,

2a + 2c = 110 — eq no. 2,

then,from eq 1,

c = 94 - 2a. —eq no. 3.

Substitute eq 3 into eq 2,

2a + 2(94 - 2a) = 110

2a - 4a = 110 - 188

-2a /-2 = -78 / -2

a = 39.

Substitute value of a into eq 3,

c = 94 - 2(39)

= 94 - 78

c = 16.

Thus, child ticket = $16.

User The Aelfinn
by
5.4k points
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