Which values of x are point(s) of discontinuity for this function? Function x = –4 x = –2 x = 0 x = 2 x = 4

Question

asked Jul 1, 2021 71.5k views

2 Answers

Piovezan · Answer 1 · 2021-07-07T13:19:12+0000

Answer:

x=0 and x=2

Explanation:

We need to check at each point where the function changes definition

At x= -2

On the left side -4 on the right side = -( -2)^2 = -4 continuous

At x=0

The point is not defined since neither side has an equals sign

discontinuous

x =2

on the left side 2^2 =4 on the right side 2

It is discontinuous