K=basketball, S= baseball
10K
5S
3 K & S
26 total
P(K) = 10/26, P(S) = 5/26 P(K^S) = 3/26
P(K v S) = P(K) + P(S) - P(K^S) = 10/26 + 5/26 - 3/26 = 12/26 = 6/13
Probability of randomly getting a student who plays either basketball or baseball = 6/13
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