Answer:
ΔFHK and ΔGHJ are the similar triangles by SAS similarity theorem.
Explanation:
Picture for the given question is missing; find the picture attached.
If
and ∠H ≅ ∠H
Then ΔFHK ~ ΔGHJ
![\frac{\text{FH}}{\text{GH}}=\frac{\text{HK}}{\text{HJ}}](https://img.qammunity.org/2021/formulas/mathematics/high-school/n7tway25qfgtypuq5t2n8rjuizz9e42p6z.png)
![((12+10))/(10)=((15+18))/(15)](https://img.qammunity.org/2021/formulas/mathematics/high-school/i250jgf9yc7wakv0gzfzarsd398iwczzs9.png)
![(22)/(10)=(33)/(15)](https://img.qammunity.org/2021/formulas/mathematics/high-school/pgpvtfey9gz4w274jtqbnnxthykr69s7du.png)
![(11)/(5)=(11)/(5)](https://img.qammunity.org/2021/formulas/mathematics/high-school/ovw2dkn9w5rxoojotwq2inqbu38sal7kpe.png)
Since,
and ∠H ≅ ∠H [By reflexive property]
Therefore, ΔFHK and ΔGHJ are the similar triangles by SAS similarity theorem.
Option (3) will be the answer.