166k views
2 votes
There were 96 people in a queue to get into a fun fair. There were at least

4 children between any 2 adults.
What was the largest possible number of adults in the queue?​

2 Answers

3 votes

Answer:

32 adulta

Explanation:

96÷6 = 16 number of families

now we need to see how many adults there are in 16 families.

and the number is 32 adults.

User JustGettinStarted
by
8.1k points
1 vote

Answer:

32 adults.

Explanation:

At the very least, there are 4 children for every 2 adults. That means that, at the very least, there are 6 people in one group to get into the fun fair.

96 / 6 = 16

So, there are 16 groups trying to get into the fun fair, with 2 adults in each group. 2 * 16 = 32 adults are in the queue.

Hope this helps!

User Peter Li
by
7.7k points

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