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1 vote
Nd the measure of angle m

2. Find the length of sie
m
18.2m
61°
15:1m
х
105mm

Nd the measure of angle m 2. Find the length of sie m 18.2m 61° 15:1m х 105mm-example-1
User DaveJenni
by
4.4k points

1 Answer

3 votes

Answer:

1). m° = 56.1°

2). X= 91.8 mm

Explanation:

For angle m°

Using the sine rule

15.1/sin m= 18.2/sin 90

But Sin 90= 1

15.1/sin m= 18.2

15.1= 18.2*sin m

Sin m = 15.1/18.2

Sin m=0.8297

m= sin^-1(0.8297)

m= 56.06°

m° = 56.1°

For length of side x

Using sine rule

X/sin 61= 105/sin 90

But sin 90= 1

X/sin 61= 105

X = sin61 *105

X=0.8746*105

X= 91.833 mm

X= 91.8 mm

User Pablo Romeo
by
4.6k points