Question

What is the equation, in point-slope form, of the line

that is parallel to the given line and passes through the
point (-3, 1)?
y-1=- Ž(x+3)
y-1=-{(x + 3)
y-1= {(x+3)
y-1= {(x+3)

Answer 1

Answer:
`(y-1)=(3)/(2)(x+3)`

Explanation:

Slope of the given line passing through (-2,-4) and (2,2) :

m=
`(y_2-y_1)/(x_2-x_1)`

`=(2-(-4))/(2-(-2))\\\\=(2+4)/(2+2)=(6)/(4)\\\\=(3)/(2)`

Parallel lines has same slope . That means slope of required line would be
`(3)/(2)`.

Equation of a line passing through (a,b) and has slope 'm' is given by :_

`(y-b)=m(x-a)`

Now, Equation of a line passing through(-3, 1) and has slope '
`(3)/(2)`' is given by

`(y-1)=(3)/(2)(x-(-3))\\\\\Rightarrow\ (y-1)=(3)/(2)(x+3)\ \ \to \text{Required equation in point slope form.}`