Question

a toy propeller fan with a moment of inertia of .034 kg x m^2 has a net torque of .11Nxm applied to it. what angular acceleration does it experience

Answer 1

The angular acceleration is
`\alpha = 3.235 \ rad/s ^2`

Step-by-step explanation:

From the question we are told that

The moment of inertia is
`I = 0.034\ kg \cdot m^2`

The net torque is
`\tau = 0.11\ N \cdot m`

Generally the net torque is mathematically represented as

`\tau = I * \alpha`

Where
`\alpha` is the angular acceleration so

`\alpha = (\tau )/(I)`

substituting values

`\alpha = (0.1 1)/( 0.034)`

`\alpha = 3.235 \ rad/s ^2`