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Find the sum of the finite geometric series.
Mr. Jamison deposited $100 into a new savings account on January 1. On the first day of each month thereafter, he deposited three times the amount he deposited in the previous month. On June 15 of the same year, the total amount Mr. Jamison has deposited is $

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Answer:

$36,400

Explanation:

Mr Jamison deposited $100 in January

February=3*100=$300

March=3{3(100)=3^2(100)=9*100=$900

April=3^3(100)=27*100=$2,700

May=3^4(100)=81*100=$8,100

June=3^5(100)=243*100=$24,300

Total amount=$100 + $300 + $900 + $2700 + $8100 + $24300

=$36,400

The total amount deposited by Mr Jamison on June 15 is $36,400

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