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is a polyprotic acid. Write balanced chemical equations for the sequence of reactions that carbonic acid can undergo when it's dissolved in water.

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Answer:

H₂CO₃ H₂O ⇄ HCO₃⁻ + H₃O⁺ Ka1

HCO₃⁻ + H₂O ⇄ CO₃⁻² + H₃O⁺ Ka2

CO₃⁻² + H₂O ⇄ HCO₃⁻ + OH⁻ Kb1

HCO₃⁻ + H₂O ⇄ H₂CO₃ + OH⁻ Kb2

Step-by-step explanation:

Formula for carbonic acid is: H₂CO₃

It is a dyprotic acid, because it can release two protons. We can also mention that is a weak one. The equilibrums are:

H₂CO₃ H₂O ⇄ HCO₃⁻ + H₃O⁺ Ka1

HCO₃⁻ + H₂O ⇄ CO₃⁻² + H₃O⁺ Ka2

When the conjugate strong bases, carbonate and bicarbonate take a proton from water, the reactions are:

CO₃⁻² + H₂O ⇄ HCO₃⁻ + OH⁻ Kb1

HCO₃⁻ + H₂O ⇄ H₂CO₃ + OH⁻ Kb2

Notice, that bicarbonate anion can release or take a proton to/from water. This is called amphoteric,

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