229k views
4 votes
Predict the sign and calculate ΔS° for a reaction. Close Problem Consider the reaction H2CO(g) + O2(g)CO2(g) + H2O(l) Based upon the stoichiometry of the reaction the sign of Sºrxn should be _________ . Using standard thermodynamic data (in the Chemistry References), calculate Sºrxn at 25°C. Sºrxn = J/K•mol

User Lucky Rana
by
5.0k points

1 Answer

2 votes

Answer:


\mathbf{S^0_(rxn) = -140.41 \ J/mol.K}

Based upon the stoichiometry of the reaction the sign of Sºrxn should be negative

Step-by-step explanation:

Consider the reaction:

H2CO(g) + O2(g) --------> CO2(g) + H2O(l)

Using standard thermodynamic data;

Based upon the stoichiometry of the reaction the sign of Sºrxn should be _________ . calculate Sºrxn at 25°C. Sºrxn = J/K•mol

At standard thermodynamic data


\mathtt{S^0_(rxn) = \sum S^0 _(product) - \sum S^0 _(reactant)}


S^0(CO_2) = 213.79 J/mol.K


S^0(H_2O)= 69.95 J/mol.K


S^0 ({H_2CO}) = 218.95 J/mol.K


S^0 (O_2) = 205.2 J/mol.K


\mathtt{S^0_(rxn) = (213.79 + 69.95) J/mol.K - (218.95+ 205.2) J/mol.K}


\mathtt{S^0_(rxn) = (283.74) J/mol.K - (424.15) J/mol.K}


\mathbf{S^0_(rxn) = -140.41 \ J/mol.K}

Based upon the stoichiometry of the reaction the sign of Sºrxn should be negative

User Imrhung
by
5.1k points