Question

What is the correct answer and how can this be solved?

Answer 1

`\boxed{\displaystyle (1)/(19)}`

Explanation:

`\displaystyle (n+2)/(2n^2 +3n-2)`

Replace n with 10 to find the 10th term.

`\displaystyle (10+2)/(2(10)^2 +3(10)-2)`

Evaluate.

`\displaystyle (12)/(2(100) +30-2)`

`\displaystyle (12)/(200 +30-2)`

`\displaystyle (12)/(228)`

Simplify.

`\displaystyle (1)/(19)`

Answer 2

`$\mathbf{(1)/(19) }`

Explanation:

`$$\bullet \Nth \ Term;\\$$$(n+2)/(2n^(2) +3n-2)`

`$$\bullet U_(10) \ Term;\\\\$$\boxed{((10+2) )/(2*10^(2) +3*10-2)= (1)/(19) }`