Question

A 5.0-µC point charge is placed at the 0.00 cm mark of a meter stick and a -4.0-µC point charge is placed at the 50 cm mark. At what point on a line joining the two charges is the electric field due to these charges equal to zero?

Answer 1

Electric field is zero at point 4.73 m

Step-by-step explanation:

Given:

Charge place = 50 cm = 0.50 m

change q1 = 5 µC

change q2 = 4 µC

Computation:

electric field zero calculated by:

`E1 =k(q1)/(r^2) \\\\E2 =k(q2)/(R^2) \\\\`

Where electric field is zero,

First distance = x

Second distance = (x-0.50)

So,

E1 = E2

`k(q1)/(r^2)=k(q2)/(R^2) \\\\`

`(5)/(x^2)=(4)/((x-50)^2) \\\\`

x = 0.263 or x = 4.73

So,

Electric field is zero at point 4.73 m