Question

An emf is induced by rotating a 1060 turn, 20.0 cm diameter coil in the Earth's 5.25 ✕ 10−5 T magnetic field. What average emf (in V) is induced, given the plane of the coil is originally perpendicular to the Earth's field and is rotated to be parallel to the field in 10.0 ms? V †

Answer 1

The average emf induced in the coil is 175 mV

Step-by-step explanation:

Given;

number of turns of the coil, N = 1060 turns

diameter of the coil, d = 20.0 cm = 0.2 m

magnitude of the magnetic field, B = 5.25 x 10⁻⁵ T

duration of change in field, t = 10 ms = 10 x 10⁻³ s

The average emf induced in the coil is given by;

`E = N(\delta \phi)/(dt) \\\\E = N(\delta B)/(\delta t)A`

where;

A is the area of the coil

A = πr²

r is the radius of the coil = 0.2 /2 = 0.1 m

A = π(0.1)² = 0.03142 m²

`E = (NBA)/(t) \\\\E = (1060*5.25*10^(-5)*0.03142)/(10*10^(-3)) \\\\E = 0.175 \ V\\\\E = 175 \ mV`

Therefore, the average emf induced in the coil is 175 mV