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When a constant force acts upon an object, the acceleration of the object varies inversely with its mass. When a certain constant force acts upon an object with mass 4kg, the acceleration of the object is 15/ms2. If the same force acts upon another object whose mass is

10kg, what is this object's acceleration?

1 Answer

5 votes

Answer:


a = 6m/s^2

Explanation:

Given

When mass = 4kg; Acceleration = 15m/s²

Required

Determine the acceleration when mass = 10kg, provided force is constant;

Represent mass with m and acceleration with a

The question says there's an inverse variation between acceleration and mass; This is represented as thus;


a\ \alpha\ (1)/(m)

Convert variation to equality


a = (F)/(m); Where F is the constant of variation (Force)

Make F the subject of formula;


F = ma

When mass = 4kg; Acceleration = 15m/s²


F = 4 * 15


F = 60N

When mass = 10kg; Substitute 60 for Force


F = ma


60 = 10 * a


60 = 10a

Divide both sides by 10


(60)/(10) = (10a)/(10)


a = 6m/s^2

Hence, the acceleration is
a = 6m/s^2

User Khay
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