Answer:
5.0 m/s
Step-by-step explanation:
If the river moves towards the south at 3m/s and the both moves towards the east at 4.0m/s, the speed of the boat relative to me will be the resulting displacement of both velocities of the river and that of the boat. This can be gotten using pythagoras theorem.
Let Vr be the relative speed. According to the theorem;
![V_r^2 = V_s^2 + V_e^2\\\\V_r^2 = 3.0^2 + 4.0^2\\\\V_r^2 = 9+16\\\\V_r^2 = √(25)\\ \\V_r = 5.0m/s](https://img.qammunity.org/2021/formulas/physics/college/5wrekrbfts64kk7kvumiz9z77br3ndajtj.png)
Hence this relative speed is 5.0 m/s