Question

A basketball is shot into the air. Its height is represented by the polynomial equation

h(t) = -16+ + 35t + 5, where h is the height of the basketball at t seconds. What's
the height of the basketball at 1.5 seconds?
18.8 feet
21.5 feet
16.7 feet
1
20.2 feet

Answer 1

21.5

Explanation:

h(t) = -16t^2 + 35t + 5,

Let t = 1.5

h(1.5) = -16 (1.5)^2 + 35(1.5) + 5

=-16 *2.25 +52.5+5

= -36+57.5

= 21.5