Complete Question
The complete question is shown on the first uploaded image
Answer:
The 95% interval for
is
![-0.0171 ,0.0411](https://img.qammunity.org/2021/formulas/mathematics/college/mrmez6ldfxad4xcpx42nzu8ulw08k3szw9.png)
Option A is correct
Explanation:
From the question we are told that
The sample size of male is
The number of males that said they have at least one tattoo is
The sample size of female is
![n_2 = 1041](https://img.qammunity.org/2021/formulas/mathematics/college/iko1gurfcwirimz0kaxja0vtztkv3ogl2r.png)
The number of females that said they have at least one tattoo is
![k = 144](https://img.qammunity.org/2021/formulas/mathematics/college/o7ceot5byl1um4yavnh9ek2fjjzkh34s5n.png)
Generally the sample proportion of male is
![\r p_1 = (r)/( n_1)](https://img.qammunity.org/2021/formulas/mathematics/college/o3t4olxd8wafscz6w6snk943d9zpzxlg1h.png)
substituting values
![\r p_1 = ( 182)/(1211)](https://img.qammunity.org/2021/formulas/mathematics/college/jqsjm4k3sd74ygtdacx5bk9ji30petvai6.png)
![\r p_1 = 0.1503](https://img.qammunity.org/2021/formulas/mathematics/college/yqfh49ylkk56kdjrbwcu4ugap3g7v9vrlm.png)
Generally the sample proportion of female is
![\r p_2 = (k)/( n_2)](https://img.qammunity.org/2021/formulas/mathematics/college/tycuc5m2g1hnn2o5khz78we0a7k64vofio.png)
substituting values
![\r p_2 = ( 144)/(1041)](https://img.qammunity.org/2021/formulas/mathematics/college/ayjhb8m2wt19r8fnf4zwpt4plx3t400gi6.png)
![\r p_2 = 0.1383](https://img.qammunity.org/2021/formulas/mathematics/college/wnw2uf8lgcyejbhruq7mqqkk3sg2yt3lt1.png)
Given that the confidence level is 95% then the level of significance is mathematically represented as
![\alpha =100-95](https://img.qammunity.org/2021/formulas/mathematics/college/st2lrr8ektn5pvvaqxok44r15gq2i5ghs7.png)
![\alpha =5\%](https://img.qammunity.org/2021/formulas/mathematics/college/jj1wdr5e7aii2h4pu2pyltcwv7sr7cv2rn.png)
![\alpha =0.05](https://img.qammunity.org/2021/formulas/mathematics/college/8skuq08m6mn2kzbj9hw8ihf5rskybetrrs.png)
Next we obtain the critical value of
from the normal distribution table , the value is
![Z_(\alpha )/(2) = 1.96](https://img.qammunity.org/2021/formulas/mathematics/college/lx72vqgk9v0207ev3our249o5r86qdm2mf.png)
Generally the margin of error is mathematically represented as
![E = Z_{(\alpha )/(2) } * \sqrt{(\r p_1 (1- \r p_1))/(n_1) + (\r p_2 (1- \r p_2))/(n_2) }](https://img.qammunity.org/2021/formulas/mathematics/college/jplac3fe9qsu7qmkxerill746pn0qcjzd5.png)
substituting values
![E = 1.96 * \sqrt{( 0.1503 (1- 0.1503))/(1211) + (0.1383 (1- 0.1383))/(1041) }](https://img.qammunity.org/2021/formulas/mathematics/college/qt49hms11fu3uxh4oqkefqcjw3l4zgfti2.png)
![E = 0.0291](https://img.qammunity.org/2021/formulas/mathematics/college/x452wjphtrdbj1zim4hltn18ltbjk3kd17.png)
The 95% confidence interval is mathematically represented as
![(\r p_1 - \r p_2 ) - E < p_1-p_2 < (\r p_1 - \r p_2 ) + E](https://img.qammunity.org/2021/formulas/mathematics/college/bj77mqtls5b1e0188w90h6h5nrut6pcgd0.png)
substituting values
![(0.1503- 0.1383 ) - 0.0291 < p_1-p_2 < (0.1503- 0.1383 ) + 0.0291](https://img.qammunity.org/2021/formulas/mathematics/college/u1kw4dbi5m5y1pqbxtufbhvhcszkuerptd.png)
![-0.0171 < p_1-p_2 < 0.0411](https://img.qammunity.org/2021/formulas/mathematics/college/av8uzig7v6qxhouyopocpwgca2aucqlomj.png)
So the interpretation is that there is 95% confidence that the difference of the proportion is in the interval .So conclude that there is insufficient evidence of a significant difference in the proportion of male and female that have at least one tattoo
This because the difference in proportion is less than
![\alpha](https://img.qammunity.org/2021/formulas/physics/high-school/hnta6o297p6x6k4chhffnl4rkouajc67r4.png)