Greetings from Brasil...
a)
Let's just use Pythagoras
L² = X² + (X - 7)²
b)
If L = 13, then what is the value of X ???
L² = 2X² - 14X + 49
2X² - 14X - 120 = 0
X = 12 or X = - 5
(The distance cannot be negative, so X = 12)
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