Answer:
The expectation is
![E(1 )= -\$ 1](https://img.qammunity.org/2021/formulas/mathematics/college/r3run8tesk4jp9re8vpuggtqn9zkwvherd.png)
Explanation:
From the question we are told that
The first offer is
![x_1 = \$ 8000](https://img.qammunity.org/2021/formulas/mathematics/college/iry1v5ak62tkt53bbd3xxjsfrjn3h9pyix.png)
The second offer is
![x_2 = \$ 4000](https://img.qammunity.org/2021/formulas/mathematics/college/j5zcw768gemdmwhb38qn9he7bujo758sek.png)
The third offer is
![\$ 1600](https://img.qammunity.org/2021/formulas/mathematics/college/dqh033ks79eu16p68klsxbxq5i8h0dnge9.png)
The number of tickets is
![n = 5000](https://img.qammunity.org/2021/formulas/mathematics/college/vdmrr01sgl2zjkiafkbx9tcibutemwf0xv.png)
The price of each ticket is
![p= \$ 5](https://img.qammunity.org/2021/formulas/mathematics/college/fkeu7x0v4k9ct49sa4mltafb88w1yjbtvy.png)
Generally expectation is mathematically represented as
![E(x)=\sum x * P(X = x )](https://img.qammunity.org/2021/formulas/mathematics/college/i4fgpnxcocdpj9f4a6sby07r8xjbs58gu6.png)
given that they just offer one
Now
given that they just offer one
Now
given that they offer five
Hence the expectation is evaluated as
![E(x)=8000 * 0.0002 + 4000 * 0.0002 + 1600 * 0.001](https://img.qammunity.org/2021/formulas/mathematics/college/48eanap6gubnl5q5bjzmg9yfexuinh51nt.png)
![E(x)=\$ 4](https://img.qammunity.org/2021/formulas/mathematics/college/hi2h94cces5a0jqm2fhrj2u88rmb8ssvpe.png)
Now given that the price for a ticket is
![\$ 5](https://img.qammunity.org/2021/formulas/mathematics/college/yk6t27go9z2kfcmx9rxm8yivvowad204fx.png)
The actual expectation when price of ticket has been removed is
![E(1 )= 4- 5](https://img.qammunity.org/2021/formulas/mathematics/college/eakr9l00btzoicqu15vmwyhj7m54ze2wcv.png)
![E(1 )= -\$ 1](https://img.qammunity.org/2021/formulas/mathematics/college/r3run8tesk4jp9re8vpuggtqn9zkwvherd.png)