Answer:
![\huge\boxed{Option\ D : \ BC = 10√(2)\ ft }](https://img.qammunity.org/2021/formulas/mathematics/high-school/dpcbbsuwzon7pozscziy5ubkq1m3idpyqk.png)
Explanation:
Since it's a right angled triangle, We'll use trigonometric rations.
Given that m∠B = 45°
So,
Sin B = opposite / hypotenuse
Where m∠B = 45°, opposite = 10 ft and hypotenuse = BC
Sin 45 = 10 / BC
![\sf (√(2) )/(2) = (10)/(BC)](https://img.qammunity.org/2021/formulas/mathematics/high-school/d0e1h8d3cr9oscjya663ma7an1c1epstnl.png)
BC = 20 / √2
Multiplying and Dividing by √2
BC = 20√2 / √(2)²
BC = 20 √2 / 2
BC = 10√2 ft