How much heat in calories must be added to change 100.0 grams of water from 19.7 - 87 9°C?

asked Jan 6, 2023 224k views

13 votes

How much heat in calories must be

added to change 100.0 grams of water
from 19.7 - 87 9°C?

7.0k points

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4 votes

Answer:

6820 calories

Step-by-step explanation:

Specific heat of water = 1 c / gm-C

100 gm * (87.9-19.7) C * 1 c/gm-C = 6820 cal

Asur answered Jan 13, 2023

by Asur

6.1k points

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