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Kelvin wants to know whether he skied without falling more than twice as long as anyone else in his family. His dad tells him that he can check by using the inequality 2f < 223, where f is the time skied in seconds for each person. Plug the values for the time skied by each person into the inequality to find the answer.

Lori 55
Vanessa 265
Devon 172
Celia 112
Arnold 356

2 Answers

3 votes

Answer:

Yes, Kevin skied 2x as long as Lori.

Explanation:

Kevin's time was 223 seconds; Lori's time was 110 seconds.

110^2 = 220 or 110 multiplied by 2 equals 220 or 110 x 2 = 220 or

110 * 2 = 220

Thus, Kevin indeed, skied twice as long as Lori.

Kelvin wants to know whether he skied without falling more than twice as long as anyone-example-1
User Flomei
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6.0k points
4 votes

Answer:

Kelvin did not skied without falling more than twice as long as anyone else in his family.

Explanation:

The inequality representing the event where Kelvin skied without falling more than twice as long as anyone else in his family is:


2f<223

Here 223 is the time for Kelvin.

  • Check for Lori as follows:


2f<223


2* 55=110<223

Kelvin skied without falling more than twice as long as Lori.

  • Check for Vanessa as follows:


2f<223


2* 265=530>223

Kelvin skied without falling less than twice as long as Vanessa.

  • Check for Devon as follows:


2f<223


2* 172=344>223

Kelvin skied without falling less than twice as long as Devon.

  • Check for Celia as follows:


2f<223


2* 112=224>223

Kelvin skied without falling less than twice as long as Celia.

  • Check for Arnold as follows:


2f<223


2* 356=712>223

Kelvin skied without falling less than twice as long as Arnold.

Thus, Kelvin did not skied without falling more than twice as long as anyone else in his family.

User Tasnuva Leeya
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5.8k points