Question

By what angle should the second polarized sheet be rotated relative to the first to reduce the transmitted intensity to one-half the intensity that was transmitted through both polarizing sheets when aligned

Answer 1

θ = 45º

Step-by-step explanation:

The light that falls on the second polarized is polarized, therefore it is governed by the law of Maluz

I = I₀ cos² θ

in the problem they ask us

I = ½ I₀

let's look for the angles

½ I₀ = I₀ cos² θ

cos θ = √ ½ = 0.707

θ = cos 0.707

θ = 45º