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A population is estimated to have a standard deviation of 9. We want to estimate the population mean within 2, with a 99% level of confidence. How large a sample is required? (Round up your answer to the next whole number.)

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Answer:

The sample required is
n = 135

Explanation:

From the question we are told that

The standard deviation is
\sigma = 9

The margin of error is
E = 2

Given that the confidence level is 99% then the level of significance is mathematically evaluated as


\alpha = 100-99


\alpha = 1 \%


\alpha = 0.01

Next we will obtain the critical value
(\alpha )/(2) from the normal distribution table(reference math dot armstrong dot edu) , the value is


Z_{(\alpha )/(2) } = Z_{(0.05 )/(2) } = 2.58

The sample size is mathematically represented as


n = [ \frac{Z_{(\alpha )/(2) } * \sigma }{E} ]^2

substituting values


n = [ ( 2.58 * 9 )/(2) ]^2


n = 135