Answer:
Last statement is the true one: AH congruent with AB
Explanation:
Since the FG is congruent with KC, then the central angles defined by this chords are the same. and since the segments AH and AB are perpendicular to the segments GF and KC respectively (intersecting them at exactly half of their length), they form right angle triangles of which the hypotenuse is the actual radius of the circle, one of the legs of these triangles is half of the segments GF and KC of equal length. Then the third legs of those right angle triangles (AH and AB) must be equal as well.