Question

deepta and abhinav having weight 450N and 350N are playing seesaw. If deepta sits at a distance of 2cm from fulcrum, how far should abhinav be seated in order to balance deepta?​

Answer 1

Abhinav be seated at "2.57 cm" far. The further explanation is given below.

Step-by-step explanation:

The given values are:

Deepta's weight,

= 450 N

Abhinav's weight,

= 350 N

Deepta's distance from fulcrum,

= 2cm

i.e.,

= 0.02 m

Let Abhinav's distance be "x".

As we know,

⇒
`Work \ done \ by \ Deepta = Work \ done \ by \ Abhinav`

⇒
`Deepta's \ weight* Deepta's \ distance = Abhinav's \\ weight* Abhinav's \ distance`

⇒
`450* 0.02=350* x`

⇒
`9=350* x`

⇒
`(9)/(350) = x`

⇒
`x=0.025 \ m`

i.e.,

⇒
`2.57 \ cm`