Answer:
The probability that the assembly line will be shut down is 0.00617.
Explanation:
We are given that a soda bottling company’s manufacturing process is calibrated so that 99% of bottles are filled to within specifications, while 1% is not within specification.
Every hour, 12 random bottles are taken from the assembly line and tested. If 2 or more bottles in the sample are not within specification, the assembly line is shut down for recalibration.
Let X = Number of bottles in the sample that are not within specification.
The above situation can be represented through binomial distribution;
![P(X=r)=\binom{n}{r} * p^(r)* (1-p)^(n-r);x=0,1,2,3,.....](https://img.qammunity.org/2021/formulas/mathematics/college/t3p1qtu0eogh56i16987g7czt4ob4mv5rq.png)
where, n = number of trials (samples) taken = 12 bottles
x = number of success = 2 or more bottles
p = probabilitiy of success which in our question is probability that
bottles are not within specification, i.e. p = 0.01
So, X ~ Binom (n = 12, p = 0.01)
Now, the probability that the assembly line will be shut down is given by = P(X
2)
P(X
2) = 1 - P(X = 0) - P(X = 1)
=
![1-\binom{12}{0} * 0.01^(0)* (1-0.01)^(12-0)-\binom{12}{1} * 0.01^(1)* (1-0.01)^(12-1)](https://img.qammunity.org/2021/formulas/mathematics/college/8mv5anhstq5899m2hbx39j59wyrkyxr9je.png)
=
![1-(1 * 1* 0.99^(12))-(12 * 0.01^(1)* 0.99^(11))](https://img.qammunity.org/2021/formulas/mathematics/college/stj9chi0zj4n2l3y39u21a5l9n01c9avv4.png)
= 0.00617