Answer: There will be 4977 bacteria present after 10 hours.
Explanation:
The exponential function for continuous growth in t years is given by :-
(i)
, where A = initial population, k= rate of growth.
As per given, A= 2000,
After t= 2 hours, P=2400
Put these values in (i), we get
Taking log on both sides
put value of A=2000, k= 0.09116 and t= 10 , we get
Hence, there will be 4977 bacteria present after 10 hours.