Question

5. The volleyball team has a double-header on Friday. The probability that they

will win both games is 38%. The probability that they will win just the first game is
70%, What is the probability that the team will win the second game given that
they have already won the first game?

Answer 1

Answer: 54.29%

Explanation:

Given: The probability that they will win both games is 38%.

i.e. P( both games will win) =0.38

The probability that they will win just the first game is 70%.

P(first game will win) = 0.70

To find : P(second game will win| first game will win)

Using formula:
`P(B|A)=\frac{P(\text{both A and B})}{P(A)}`

So, P(second game will win| first game will win) =
`\frac{\text{ P( both games will win)}}{\text{P(first game will win)}}`

`=(0.38)/(0.70)\approx0.5429=54.29\%`

Hence, the required probability = 54.29%