215k views
4 votes
A company determined that for each $1 increase in the price of their product, the

number of items sold will decrease by 2. Their predicted weekly profit with a

price increase of x dollars is represented by the function

f(x)= – 2x2+20x +150.


By how many dollars

should they increase the price of their product to

maximize their weekly profits?


15


200


150


5

2 Answers

3 votes
They would have to increase it by 5$ so that they can maximize their weekly profit!
User Ben Thielker
by
8.0k points
7 votes

Answer:

To have maximum profit, the price must be increased by 5,

Explanation:

Given that the price increase function is:

f(x) = -2x² + 20x + 150,

For maximum profit, then f(x) = 0.

Putting f(x) = 0, we have

-2x² + 20x + 150 = 0

Or

x² - 10x - 75 = 0

(x + 5)(x - 15) = 0

x = -5

Or

x = 15

Again, differentiating f(x) and equating to zero, we have

-4x + 20 = 0

4x = 20

x = 20/4

= 5

To have maximum profit, the price must be increased by 5,

User Kilon
by
7.7k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories