Answer:
(0.102, -0.062)
Explanation:
sample size in 2018 = n1 = 216
sample size in 2017 = n2 = 200
number of people who went for another degree in 2018 = x1 = 54
number of people who went for another degree in 2017 = x2 = 46
p1 = x1/n1 = 0.25
p2 = x2/n2 = 0.23
At 95% confidence level, z critical = 1.96
now we have to solve for the confidence interval =
![p1 -p2 ± z*√(((1-p1)*p1)/n1 + ((1-p2)*p2/n2)](https://img.qammunity.org/2021/formulas/mathematics/college/uzuta5s46uyik8wln62gnykfawist3vc6l.png)
![0.25 -0.23 ± 1.96*√(((1 - 0.25) * 0.25)/216 + ((1 - 0.23) *0.23/200)](https://img.qammunity.org/2021/formulas/mathematics/college/yjj3hkm1nagy2a5ae28ika2ss3y5km4hxt.png)
= 0.02 ± 1.96 * 0.042
= 0.02 + 0.082 = 0.102
= 0.02 - 0.082 = -0.062
There is 95% confidence that there is a difference that lies between - 0.062 and 0.102 on the proportion of students who continued their education in the years, 2017 and 2018.
There is no significant difference between the two.