Question

-50 POINTS- please help

Answer 1

`\Large \boxed{\bold{D.} \ \left[\begin{array}{ccc}-13\\ -10\end{array}\right]}`

Explanation:

`AX=B`

To find
`X`

`X=A^(-1) \cdot B`

`\displaystyle \left[\begin{array}{ccc}-(3)/(2) \cdot 2 + - (5)/(2) \cdot 4\\ -1 \cdot 2 + -2 \cdot 4\end{array}\right]`

`\displaystyle \left[\begin{array}{ccc}-3 + - 10\\ -2 + -8\end{array}\right]`

`\displaystyle \left[\begin{array}{ccc}-13\\ -10\end{array}\right]`

Answer 2

-13

-10

Explanation:

A x = B

To find X

A ^ -1 A x = A ^ -1 B

x = A^ -1 B

x = -3/2 -5/2 2

-1 -2 4

Across times down

-3/2 * 2 + -5/2 *4 = -13

-1 *2 -2 * 4 = -10

The matrix is

-13

-10