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What the answer now

What the answer now-example-1
User Alon Segal
by
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1 Answer

4 votes

Answer:

Area of the triangle = 98.1 km²

Explanation:

In the given triangle WXV,

m∠W + m∠X + m∠V = 180°

m∠W + 119° + 34° = 180°

m∠W = 180° - 153°

m∠W = 27°

By applying Sine rule in the given triangle,


\frac{\text{SInW}}{\text{XV}}=\frac{\text{SinX}}{\text{WV}}


\frac{\text{SIn27}}{\text{XV}}=\frac{\text{Sin119}}{26}


XV=\frac{26* (\text{Sin27})}{\text{Sin119}}

XV = 13.496 km

Area of the ΔWXV =
(1)/(2)(\text{WV})(\text{XV})(\text{SinV})

=
(1)/(2)(26)(13.496)(0.55919)

= 98.109

98.1 km²

User Mshameer
by
7.9k points

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