Question

(A LOT OF POINTS) Given the linear equation 2x + y = 6, perform the necessary operations to put the equation into the proper general form. Explain in complete sentences how you knew that the equation was in the proper general form. Complete your work in the space provided or upload a file that can display math symbols if your work requires it. Include the entire process for establishing the general form of the equation and the general form.

Answer 1

`\boxed{2x+y-6=0}`

Explanation:

`\sf The \ general \ form \ for \ the \ equation \ of \ a \ line \ is \ given \ as \ Ax+By+C=0.`

`2x+y=6`

`\sf Subtract \ 6 \ from \ both \ sides.`

`2x+y-6=6-6`

`2x+y-6=0`

`\sf A=2 \ \ \ B = 1 \ \ \ C=-6`

`\sf The \ equation \ is \ in \ general \ form.`

`\sf Graph \ equation:`

Answer 2

`\huge\boxed{2x + y - 6 = 0}`

Explanation:

2x + y = 6

Subtracting both sides by 6

2x + y - 6 = 0

Comparing it with the general form of equation
`\sf Ax+By +C = 0` , we get:

A = 2, B = 1 and C = -6.

So, the equation is in proper general form.