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Please answer this question now-example-1
User Pointy
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Answer:

Measure of arc CD = 112°

Explanation:

Since quadrilateral ABCD is a cyclic quadrilateral,

m∠A + m∠C = 180°

129° + m∠C = 180°

m∠C = 180° - 129°

m∠C = 51°

Since, m(arc BD) = 2(m∠C) [Since measure of the arc is double of its inscribed angle]

= 2(51°)

= 102°

Since, m(arc BD) + m(arc CD) + m(arc BC) = 360°

102° + m(arc CD) + 146° = 360°

m(arc CD) = 360° - (102° + 146°)

= 112°

Therefore, measure of arc CD is 112°.

User Dipesh Gupta
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