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Find the distance between points K(−1, −3) and L(0, 0). Round to the nearest tenth.

User DV Dasari
by
7.6k points

2 Answers

0 votes

Answer:

d = √10

Explanation:


K(-1, -3) , L(0, 0).\\\\d=√(((x_2-x_1)^2+ (y_2-y_1)^2) ) \\\\x_1 =-1\\\\y_1 =-3\\\\x_2 =0\\\\y_2 =0 \\\\d = √((0-(-1))^2+(0-(-3))^2)\\\\ d = √((0+1)^2+(0+3)^2)\\\\ d = √((1)^2 + (3)^2)\\\\ d = √(1 + 9)\\\\ d = √(10) \\

User SyncroIT
by
8.3k points
4 votes

Answer:


\huge\boxedKL

Explanation:

METHOD 1:

The formula of a distance between two points (x₁; y₁) and (x₂; y₂):


d=√((x_2-x_1)^2+(y_2-y_1)^2)

We have K(-1; -3) and L(0; 0). Substitute:


|KL|=√((0-(-3))^2+(0-(-1))^2)=√(3^2+1^2)=√(9+1)=√(10)}

METHOD 2:

Look at the picture.

We have the right triangle with the legs 3 and 1.

Use the Pythagorean theorem:


leg^2+leg^2=hypotenuse^2

substitute:


3^2+1^2=|KL|^2\\\\|KL|^2=9+1\\\\|KL|^2=10\to|KL|=√(10)

Find the distance between points K(−1, −3) and L(0, 0). Round to the nearest tenth-example-1
User Heinz
by
8.3k points

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