Question

Need help please! what is the total length of a 20 mm steel coiled like a spring with a 16 turns and an outer diameter of 600 mm. pitch is 300 mm. Show your solution please coz i don't really know how to do it! thanks

Answer 1

L = 29,550 mm (as per BS8110 the length is to the nearest 25)

Explanation:

Lets make it so simple and easy.

Let A = 600mm

Let B = 300mm

Let C = 16 as number turns

Let d = 20mm

L =
`\sqrt{(3.14 * (600 - 20))^(2) + 300^(2)` x 16

L = 29,550 mm (as per BS8110 the length is to the nearest 25)