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Solve for p 9(p-4)=-18

User Kamali
by
8.9k points

2 Answers

6 votes

Answer:


\boxed{p = 2}

Explanation:


\mathsf{9(p - 4) = - 18}

Distribute 9 through the parentheses


\mathsf{9p - 36 = - 18}

Move constant to R.H.S and change it's sign


\mathsf{9p = - 18 + 36}

Calculate


\mathsf{9p = 18}

Divide both sides of the equation by 9


\mathsf{ (9p)/(9) = (18)/(9) }

Calculate


\mathsf{p = 2}


\mathcal{Hope \: I \: helped}


\mathcal{Best \: regards}

User Tommi Kyntola
by
7.9k points
2 votes

Answer:

The answer is

p = 2

Explanation:

9(p-4)=-18

First expand the terms in the bracket

that's

9p - 36 = - 18

Group like terms

Send the constants to the right side of the equation

That's

9p = - 18 + 36

9p = 18

Divide both sides by 9

That's

9p/9 = 18/9

We have the final answer as

p = 2

Hope this helps you

User SidMorad
by
8.9k points

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