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What the answer now

What the answer now-example-1
User JonaGik
by
4.4k points

1 Answer

5 votes

Answer:

35.6 yd²

Explanation:

Area of ∆UVW can be solved if we know the lengths of 2 sides and their included angle.

We are Given just 1 side, UV (w). Use the law of sines to find UW (v).

Thus:


(v)/(sin(V)) = (w)/(sin(W))

W = 137°

w = 19 yd

V = 180 - (137 + 22) = 21° => sum of triangle

v = ??

Plug in the values and solve for v


(v)/(sin(21)) = (19)/(sin(137))

Multiply both sides by sin(21)


(v)/(sin(21))*sin(21) = (19)/(sin(137))*sin(21)


v = (19*sin(21))/(sin(137))


v = 10 yd (approximated)

Find area of ∆UVW:

Area = ½*UV*UW*sin(U)

Area = ½*v*w*sin(U)

= ½*10*19*sin(22)

Area = 35.6 yd² (to nearest tenth)

User Haritz Laboa
by
4.5k points