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Ahmad has some files.

He gave 3/5 of the files and had 14 files left.

How many files did he have at first?​

User Alqin
by
5.9k points

2 Answers

6 votes

Answer:

35 files

Explanation:

gave=3/5

left=2/5 = 14f

had= 5/5

2/5=14

5/5

5×14÷2 = 35

User Mohosyny
by
6.2k points
0 votes

Answer:

The answer is 35

Explanation:

Let the number of files he had be x

He gave 3/5 of the files

That's

3/5x

After that he still had 14 files left which means when we subtract 14 from the original files we should get 3/5 of the original files

So we subtract 14 from the original number of files

That's

x - 14

We equate the two statements

that's


(3)/(5) x = x - 14

Multiply through by 5


5 * (3)/(5) x = 5x - 70

We have

3x = 5x - 70

3x - 5x = 70

-2x = - 70

Divide both sides by -2

We have the final answer as

x = 35

Therefore he had 35 files at first

Hope this helps you

User Adhara
by
6.0k points