Question

X^{2m+n} * x^{n-m} / x^{m+2n}

Answer 1

`\boxed{1}`

Explanation:

`x^(2m+n) * x^(n-m) / x^(m+2n)`

When bases are same for exponents in division, subtract exponents.

`x^(2m+n) * x^(n-m-(m+2n))`

`x^(2m+n) * x^(n-m-m-2n)`

`x^(2m+n) * x^(-n-2m)`

When bases are same for exponents in multiplication, add exponents.

`x^(2m+n+-n-2m)`

`x^(2m+0-2m)`

`x^0`

Any base with power or exponent of 0 is 1.

`x^(0)=1`

Answer 2

=x

Explanation: