X^{2m+n} * x^{n-m} / x^{m+2n}

Question

asked Oct 7, 2021 213k views

2 Answers

Just Lerning · Answer 1 · 2021-10-09T10:24:10+0000

Answer:

$\boxed{1}$

Explanation:

x^(2m+n) * x^(n-m) / x^(m+2n)

When bases are same for exponents in division, subtract exponents.

x^(2m+n) * x^(n-m-(m+2n))

x^(2m+n) * x^(n-m-m-2n)

x^(2m+n) * x^(-n-2m)

When bases are same for exponents in multiplication, add exponents.

x^(2m+n+-n-2m)

x^(2m+0-2m)

x^0

Any base with power or exponent of 0 is 1.

x^(0)=1