124k views
5 votes
6. Find the focus for the parabola.
2x=(y+3)^2+14
Focus: (x,y) =

6. Find the focus for the parabola. 2x=(y+3)^2+14 Focus: (x,y) =-example-1
User Ben Adam
by
8.4k points

1 Answer

4 votes

Answer: Focus = (7.5, -3)

Explanation:

The Vertex form of a horizontal parabola is: x = a(y - k)² + h where

  • a is the vertical stretch;
    a=(1)/(4p)
  • p is the distance from the vertex to the focus
  • (h, k) is the vertex

Rewrite the equation in Vertex form to identify a, h, & k:

2x = (y + 3)² + 14


x=((y+3)^2+14)/(2)\\\\x=(1)/(2)(y+4)^2+7

Vertex: (h, k) = (7, -3)


a=(1)/(2)

Find p and then find the focus: Focus = (h + p, k)


a=(1)/(4p)\quad \rightarrow \quad (1)/(2)=(1)/(4p)\quad \rightarrow \quad 4p=2\quad \rightarrow \quad p=(2)/(4)\quad \rightarrow p=(1)/(2)\\

Focus: (7 +
(1)/(2) , -3) = (7.5, -3)

User Chuk Ultima
by
7.9k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories