Question

Find the equation of the circle in standard form for the given center (h, k) and radius R:(H,K)=(4/3,-8/8),R=1/3

Answer 1

The answer is option B

Explanation:

Equation of a circle is given by

( x - h)² + ( y - k)² = r²

where r is the radius and

( h , k) is the center of the circle

From the question the radius R = 1/3

the center ( h ,k ) = (4/3 , -8/3)

Substituting the values into the above equation

We have

`(x - (4)/(3) )^(2) + {(y - - (8)/(3)) }^(2) = ({ (1)/(3) })^(2)`

We have the final answer as

`(x - (4)/(3) )^(2) + {(y + (8)/(3)) }^(2) = (1)/(9)`

Hope this helps you