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The average daily volume of a computer stock in 2011 was ų=35.1 million shares, according to a reliable source. A stock analyst believes that the stock volume in 2014 is different from the 2011 level. Based on a random sample of 30 trading days in 2014, he finds the sample mean to be 32.7 million shares, with a standard deviation of s=14.6 million shares. Test the hypothesis by constructing a 95% confidence interval. Complete a and b A. State the hypothesis B. Construct a 95% confidence interval about the sample mean of stocks traded in 2014.

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Answer:

a

The null hypothesis is
H_o : \mu = 35 .1 \ million \ shares

The alternative hypothesis
H_a : \mu \\e 35.1\ million \ shares

b

The 95% confidence interval is
27.475 < \mu < 37.925

Explanation:

From the question the we are told that

The population mean is
\mu = 35.1 \ million \ shares

The sample size is n = 30

The sample mean is
\= x = 32.7 \ million\ shares

The standard deviation is
\sigma = 14.6 \ million\ shares

Given that the confidence level is
95\% then the level of significance is mathematically represented as


\alpha = 100-95


\alpha = 5\%

=>
\alpha = 0.05

Next we obtain the critical value of
(\alpha )/(2) from the normal distribution table

The value is
Z_{(\alpha )/(2) } = 1.96

Generally the margin of error is mathematically represented as


E = Z_{(\alpha )/(2) } * ( \sigma )/(√(n) )

substituting values


E = 1.96 * ( 14.6 )/(√(30) )


E = 5.225

The 95% confidence interval confidence interval is mathematically represented as


\= x -E < \mu < \= x +E

substituting values


32.7 - 5.225 < \mu < 32.7 + 5.225


27.475 < \mu < 37.925

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