Answer:
Explanation:
We have that
A = 51°, b = 14, c = 6
step 1
find the value of a
Applying the law of cosines
a²=c²+b²-2*c*b*cos A
a²=6²+14²-2*6*14*cos 51-------> 126.27
a=11.2
we know that
The sum of the lengths of any two sides of a triangle is greater than the length of the third side.
we have
a=11.2
b=14
c=6
so
(a+b) > c-------------> (11.2+14)=25.2
25.2 > 6-----> is not correct
therefore
the answer is the option
a. No triangles possible
I don't know if i am right sorry if this is wrong